{"id":43209,"date":"2021-11-19T01:13:59","date_gmt":"2021-11-18T18:13:59","guid":{"rendered":"https:\/\/ben.com.vn\/tin-tuc\/?p=43209"},"modified":"2024-10-07T13:20:20","modified_gmt":"2024-10-07T06:20:20","slug":"cach-tinh-phan-tram","status":"publish","type":"post","link":"https:\/\/ben.com.vn\/tin-tuc\/cach-tinh-phan-tram\/","title":{"rendered":"C\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m chi\u1ebft kh\u1ea5u, gi\u1ea3m gi\u00e1,… nhanh v\u00e0 ch\u00ednh x\u00e1c nh\u1ea5t"},"content":{"rendered":"\t\t
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\n\t\t\t\t\tC\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m<\/strong> l\u00e0 m\u1ed9t trong nh\u1eefng c\u00f4ng th\u1ee9c to\u00e1n h\u1ecdc \u0111\u01b0\u1ee3c \u1ee9ng d\u1ee5ng nhi\u1ec1u nh\u1ea5t v\u00e0o th\u1ef1c t\u1ebf. T\u1eeb c\u00f4ng th\u1ee9c ph\u1ea7n tr\u0103m c\u01a1 b\u1ea3n, c\u00e1c b\u1ea1n c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng \u0111\u1ec3 t\u00ednh to\u00e1n ch\u00ednh x\u00e1c \u0111\u01b0\u1ee3c t\u1ec9 l\u1ec7 c\u0169ng nh\u01b0 t\u01b0\u01a1ng quan tr\u1ecdng s\u1ed1 trong nhi\u1ec1u l\u0129nh v\u1ef1c kh\u00e1c nhau. \u1ede b\u00e0i vi\u1ebft n\u00e0y, Ben Computer s\u1ebd li\u1ec7t k\u00ea c\u1ee5 th\u1ec3 cho c\u00e1c b\u1ea1n c\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m gi\u1ea3m gi\u00e1, thu\u1ebf, chi\u1ebft kh\u1ea5u,… m\u1ed9t c\u00e1ch chi ti\u1ebft nh\u1ea5t.\r\n\r\n\"c\u00e1ch\r\n

H\u01b0\u1edbng d\u1eabn c\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m chi ti\u1ebft, \u0111\u01a1n gi\u1ea3n, d\u1ec5 hi\u1ec3u<\/em><\/p>\r\n\r\n

I. C\u00f4ng th\u1ee9c t\u00ednh ph\u1ea7n tr\u0103m c\u01a1 b\u1ea3n<\/strong><\/h2>\r\nC\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m th\u01b0\u1eddng \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng trong c\u00e1c tr\u01b0\u1eddng h\u1ee3p sau: So s\u00e1nh t\u1ef7 l\u1ec7 c\u1ee7a m\u1ed9t y\u1ebfu t\u1ed1 so v\u1edbi y\u1ebfu t\u1ed1 c\u00f2n l\u1ea1i ho\u1eb7c x\u00e1c \u0111\u1ecbnh tr\u1ecdng s\u1ed1 c\u1ee7a m\u1ed9t nh\u00e2n t\u1ed1 so v\u1edbi t\u1ed5ng s\u1ed1.\r\n\r\nC\u00f4ng th\u1ee9c t\u00ednh ph\u1ea7n tr\u0103m th\u00f4ng th\u01b0\u1eddng nh\u01b0 sau:\r\n
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  • T\u00ednh t\u1ec9 l\u1ec7 c\u1ee7a a so v\u1edbi b: (a\/b) x 100%<\/strong><\/li>\r\n \t
  • T\u00ednh t\u1ec9 l\u1ec7 c\u1ee7a b so v\u1edbi a: (b\/a) x 100%<\/strong><\/li>\r\n<\/ul>\r\nV\u00ed d\u1ee5 1:<\/strong> Hai b\u1ea1n Lan v\u00e0 Huy c\u00f9ng nh\u1eadn m\u1ed9t c\u00f4ng vi\u1ec7c g\u1ea5p l\u00ec x\u00ec cho m\u1ed9t c\u1eeda h\u00e0ng nh\u1ecf \u0111\u1ec3 chu\u1ea9n b\u1ecb cho d\u1ecbp T\u1ebft, trong 1 tu\u1ea7n, b\u1ea1n Lan g\u1ea5p \u0111\u01b0\u1ee3c 120 chi\u1ebfc trong khi \u0111\u00f3, b\u1ea1n Huy g\u1ea5p \u0111\u01b0\u1ee3c 200 chi\u1ebfc. So s\u00e1nh t\u1ec9 l\u1ec7 ph\u1ea7n tr\u0103m s\u1ed1 l\u00ec x\u00ec b\u1ea1n Lan g\u1ea5p \u0111\u01b0\u1ee3c v\u1edbi s\u1ed1 l\u00ec x\u00ec c\u1ee7a b\u1ea1n Huy.\r\n\r\n=> 120\/200 x 100% = 60%\r\n\r\n=> S\u1ed1 l\u00ec x\u00ec b\u1ea1n Lan g\u1ea5p \u0111\u01b0\u1ee3c ch\u1ec9 b\u1eb1ng 60% s\u1ed1 l\u00ec x\u00ec b\u1ea1n Huy g\u1ea5p \u0111\u01b0\u1ee3c.\r\n\r\n\"C\u00f4ng\r\n

    C\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m c\u01a1 b\u1ea3n<\/em><\/p>\r\nV\u00ed d\u1ee5 2:<\/strong> L\u1edbp A c\u00f3 30 h\u1ecdc sinh, trong \u0111\u00f3 c\u00f3 20 h\u1ecdc sinh gi\u1ecfi v\u00e0 10 h\u1ecdc sinh kh\u00e1. T\u00ednh l\u1ea7n l\u01b0\u1ee3t t\u1ec9 l\u1ec7 ph\u1ea7n tr\u0103m s\u1ed1 h\u1ecdc sinh gi\u1ecfi v\u00e0 h\u1ecdc sinh kh\u00e1 so v\u1edbi t\u1ed5ng s\u1ed1 h\u1ecdc sinh trong l\u1edbp.\r\n\r\n=> T\u1ec9 l\u1ec7 ph\u1ea7n tr\u0103m s\u1ed1 h\u1ecdc sinh gi\u1ecfi so v\u1edbi t\u1ed5ng s\u1ed1 h\u1ecdc sinh: (20\/30) x 100% = 66,7 %<\/strong>\r\n\r\n=> T\u1ec9 l\u1ec7 ph\u1ea7n tr\u0103m s\u1ed1 h\u1ecdc sinh kh\u00e1 so v\u1edbi t\u1ed5ng s\u1ed1 h\u1ecdc sinh: (10\/30) x 100% = 33.3 %<\/strong>\r\n\r\nNgo\u00e0i ra, d\u1ef1a tr\u00ean t\u1ec9 l\u1ec7 ph\u1ea7n tr\u0103m v\u00e0 m\u1ed9t y\u1ebfu t\u1ed1, t\u1eeb c\u00f4ng th\u1ee9c t\u00ednh ph\u1ea7n tr\u0103m, c\u00e1c b\u1ea1n c\u00f3 th\u1ec3 t\u00ednh \u0111\u01b0\u1ee3c y\u1ebfu t\u1ed1 c\u00f2n l\u1ea1i.\r\n\r\nC\u00f4ng th\u1ee9c<\/strong>: a chi\u1ebfm c% b, t\u00ednh a => a = (b\/100) x c<\/strong>\r\n\r\nV\u00ed d\u1ee5:<\/strong> T\u1ed5ng s\u1ed1 bi l\u00e0 30 vi\u00ean. Trong \u0111\u00f3 10% l\u00e0 bi \u0111\u1ecf. T\u00ednh s\u1ed1 bi \u0111\u1ecf.\r\n\r\n=> S\u1ed1 bi \u0111\u1ecf l\u00e0: (30\/100) x 10 = 3 vi\u00ean\r\n

    II. \u1ee8ng d\u1ee5ng t\u00ednh ph\u1ea7n tr\u0103m v\u00e0o th\u1ef1c t\u1ebf<\/strong><\/h2>\r\n

    1. C\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m chi\u1ebft kh\u1ea5u gi\u1ea3m gi\u00e1<\/strong><\/h3>\r\nCh\u1eafc h\u1eb3n c\u00e1c b\u1ea1n \u0111\u00e3 quen thu\u1ed9c v\u1edbi nh\u1eefng voucher gi\u1ea3m gi\u00e1 10%, 20% khi \u0111i mua h\u00e0ng h\u00f3a. V\u1eady l\u00e0m th\u1ebf n\u00e0o \u0111\u1ec3 t\u00ednh \u0111\u01b0\u1ee3c c\u1ee5 th\u1ec3 s\u1ed1 ti\u1ec1n \u0111\u01b0\u1ee3c gi\u1ea3m khi bi\u1ebft ph\u1ea7n tr\u0103m gi\u1ea3m gi\u00e1.\r\n
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    • C\u00f4ng th\u1ee9c:<\/strong><\/li>\r\n<\/ul>\r\n

      S\u1ed1 ti\u1ec1n \u0111\u01b0\u1ee3c gi\u1ea3m = (S\u1ed1 ti\u1ec1n g\u1ed1c\/100) x ph\u1ea7n tr\u0103m gi\u1ea3m gi\u00e1<\/strong><\/p>\r\n\r\n

        \r\n \t
      • V\u00ed d\u1ee5:<\/strong> M\u1ed9t chi\u1ebfc \u00e1o c\u00f3 gi\u00e1 350.000 \u0111\u1ed3ng. C\u1eeda h\u00e0ng tri \u00e2n kh\u00e1ch h\u00e0ng, gi\u1ea3m gi\u00e1 20% to\u00e0n b\u1ed9 s\u1ea3n ph\u1ea9m. V\u1eady s\u1ed1 ti\u1ec1n \u0111\u01b0\u1ee3c gi\u1ea3m l\u00e0 bao nhi\u00eau?<\/li>\r\n<\/ul>\r\n=> S\u1ed1 ti\u1ec1n \u0111\u01b0\u1ee3c gi\u1ea3m = (350.000\/100) x 20 = 70.000 \u0111\u1ed3ng\r\n\r\n\"C\u00e1ch\r\n

        C\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m gi\u1ea3m gi\u00e1<\/em><\/p>\r\n\r\n

        2. C\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m l\u01b0\u01a1ng<\/strong><\/h3>\r\nTh\u00f4ng th\u01b0\u1eddng, c\u00f4ng th\u1ee9c t\u00ednh ph\u1ea7n tr\u0103m c\u0169ng \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng khi t\u00ednh l\u01b0\u01a1ng theo hoa h\u1ed3ng nh\u1eadn \u0111\u01b0\u1ee3c t\u1eeb t\u1ed5ng doanh s\u1ed1 b\u00e1n h\u00e0ng.\r\n\r\nC\u00f4ng th\u1ee9c: <\/strong>\r\n

        a = (b\/100) x c %<\/strong><\/p>\r\nTrong \u0111\u00f3: a l\u00e0 l\u01b0\u01a1ng \u0111\u01b0\u1ee3c nh\u1eadn, b l\u00e0 doanh s\u1ed1 b\u00e1n t\u1eeb qu\u00e1 tr\u00ecnh l\u00e0m vi\u1ec7c, c l\u00e0 ph\u1ea7n tr\u0103m hoa h\u1ed3ng \u0111\u01b0\u1ee3c c\u00f4ng ty quy \u0111\u1ecbnh.\r\n\r\n\"C\u00e1ch\r\n

        C\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m l\u01b0\u01a1ng<\/em><\/p>\r\nV\u00ed d\u1ee5:<\/strong> Theo quy \u0111\u1ecbnh c\u1ee7a m\u1ed9t trung t\u00e2m Ti\u1ebfng Anh, m\u1ed9t nh\u00e2n vi\u00ean b\u00e1n h\u00e0ng s\u1ebd \u0111\u01b0\u1ee3c h\u01b0\u1edfng l\u01b0\u01a1ng 10% tr\u00ean t\u1ed5ng doanh s\u1ed1 b\u00e1n h\u00e0ng. Trong th\u00e1ng n\u00e0y, b\u1ea1n X t\u01b0 v\u1ea5n v\u00e0 k\u00fd th\u00e0nh c\u00f4ng v\u1edbi 10 b\u1ea1n h\u1ecdc vi\u00ean. T\u1ed5ng doanh thu c\u1ee7a b\u1ea1n l\u00e0 32.000.000 \u0111\u1ed3ng.\r\n\r\n=> Nh\u01b0 v\u1eady, l\u01b0\u01a1ng th\u00e1ng n\u00e0y c\u1ee7a b\u1ea1n l\u00e0: (32.000.000\/100) x 10% = 3.200.000 \u0111\u1ed3ng\r\n

        3. C\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m l\u00e3i su\u1ea5t<\/strong><\/h3>\r\nC\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m l\u00e3i su\u1ea5t th\u01b0\u1eddng \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng trong tr\u01b0\u1eddng h\u1ee3p mu\u1ed1n x\u00e1c \u0111\u1ecbnh s\u1ed1 ti\u1ec1n l\u00e3i nh\u1eadn \u0111\u01b0\u1ee3c khi g\u1eedi ti\u1ec1n ti\u1ebft ki\u1ec7m trong ng\u00e2n h\u00e0ng. Th\u00f4ng th\u01b0\u1eddng, g\u1eedi ti\u1ebft ki\u1ec7m trong ng\u00e2n h\u00e0ng s\u1ebd \u0111\u01b0\u1ee3c chia theo k\u1ef3 h\u1ea1n: b\u1ea1n c\u00f3 th\u1ec3 g\u1eedi kh\u00f4ng th\u1eddi h\u1ea1n, g\u1eedi theo th\u00e1ng, theo n\u0103m,… \u0110\u1ed1i v\u1edbi m\u1ed7i lo\u1ea1i, % l\u00e3i su\u1ea5t s\u1ebd kh\u00e1c nhau.\r\n\r\nC\u00f4ng th\u1ee9c:<\/strong>\r\n

        Ti\u1ec1n l\u00e3i = S\u1ed1 ti\u1ec1n g\u1eedi x L\u00e3i su\u1ea5t( % n\u0103m) x (S\u1ed1 ng\u00e0y g\u1eedi\/365)<\/strong><\/p>\r\nV\u00ed d\u1ee5:<\/strong> B\u00e0 A g\u1eedi 100.000.000 ti\u1ec1n ti\u1ebft ki\u1ec7m v\u00e0o ng\u00e2n h\u00e0ng Vietinbank v\u1edbi th\u1eddi h\u1ea1n 2 n\u0103m (24 th\u00e1ng). L\u00e3i su\u1ea5t quy \u0111\u1ecbnh \u0111\u01b0\u1ee3c nh\u1eadn l\u00e0 7% 1 n\u0103m.\r\n\r\n=> Nh\u01b0 v\u1eady, s\u1ed1 ti\u1ec1n l\u00e3i nh\u1eadn \u0111\u01b0\u1ee3c sau 2 n\u0103m l\u00e0: 100.000.000 x (7\/100) x (730\/365) = 14.000.000 VN\u0110\r\n\r\n\"C\u00e1ch\r\n

        C\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m l\u00e3i su\u1ea5t<\/em><\/p>\r\n\r\n

        4. C\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m l\u1ee3i nhu\u1eadn<\/strong><\/h3>\r\nV\u1ec1 c\u01a1 b\u1ea3n, c\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m l\u1ee3i nhu\u1eadn \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng trong kinh doanh, khi so s\u00e1nh ph\u1ea7n l\u1ee3i nhu\u1eadn \u0111\u1ea1t \u0111\u01b0\u1ee3c so v\u1edbi t\u1ed5ng doanh thu khi \u0111\u1ea7u t\u01b0 ho\u1eb7c b\u00e1n h\u00e0ng.\r\n\r\nC\u00f4ng th\u1ee9c:\u00a0<\/strong>\r\n

        % l\u1ee3i nhu\u1eadn = ( N\u0103m sau – N\u0103m tr\u01b0\u1edbc)\/ N\u0103m tr\u01b0\u1edbc x 100<\/strong><\/p>\r\nV\u00ed d\u1ee5:<\/strong> M\u1ed9t doanh nghi\u1ec7p X c\u00f3 m\u1ee9c doanh thu n\u0103m 2020 l\u00e0 200 t\u1ef7 \u0111\u1ed3ng, doanh thu n\u0103m 2019 l\u00e0 150 t\u1ef7 \u0111\u1ed3ng.\r\n\r\n=> Nh\u01b0 v\u1eady, ph\u1ea7n tr\u0103m l\u1ee3i nhu\u1eadn c\u1ee7a c\u00f4ng ty s\u1ebd \u0111\u01b0\u1ee3c t\u00ednh theo c\u00f4ng th\u1ee9c:\r\n

        %l\u1ee3i nhu\u1eadn = ( 200 – 150 )\/150 x 100 = 33,33 %<\/p>\r\n\"C\u00e1ch\r\n

        C\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m l\u1ee3i nhu\u1eadn<\/em><\/p>\r\n\r\n

        III. H\u01b0\u1edbng d\u1eabn c\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m trong Excel<\/strong><\/h2>\r\nKhi s\u1eed d\u1ee5ng Excel, thay v\u00ec t\u00ednh th\u1ee7 c\u00f4ng ph\u1ee9c t\u1ea1p, c\u00e1c b\u1ea1n c\u00f3 th\u1ec3 s\u1eed d\u1ee5ng c\u00f4ng th\u1ee9c ph\u1ea7n tr\u0103m trong Excel \u0111\u1ec3 vi\u1ec7c t\u00ednh to\u00e1n tr\u1edf n\u00ean \u0111\u01a1n gi\u1ea3n h\u01a1n.\r\n\r\n\u0110\u1ec3 th\u1ef1c hi\u1ec7n c\u00e1c t\u00ednh ph\u1ea7n tr\u0103m tr\u00ean Excel, b\u1ea1n th\u1ef1c hi\u1ec7n nh\u01b0 sau: Ch\u1ecdn \u00f4 b\u1ea1n \u0111\u1eb7t c\u00f4ng th\u1ee9c t\u00ednh ph\u1ea7n tr\u0103m<\/strong> => ch\u1ecdn Home<\/strong> => T\u1ea1i m\u1ee5c Number<\/strong>, ch\u1ecdn bi\u1ec3u t\u01b0\u1ee3ng %<\/strong>.\r\n\r\nV\u00ed d\u1ee5:<\/strong> T\u1ea1i \u00f4 D2, c\u00e1c b\u1ea1n mu\u1ed1n t\u00ednh k\u1ebft qu\u1ea3 ph\u1ea7n tr\u0103m c\u1ee7a B2\/C2, h\u00e3y nh\u1eadp = B2\/C2 => Trong tab Home, t\u1ea1i \u00f4 Number, ch\u1ecdn bi\u1ec3u t\u01b0\u1ee3ng % <\/strong>=> Enter. <\/strong>Sau \u0111\u00f3, k\u1ebft qu\u1ea3 \u00f4 s\u1ebd hi\u1ec3n th\u1ecb % \u0111\u01b0\u1ee3c l\u00e0m tr\u00f2n nh\u01b0 b\u00ean d\u01b0\u1edbi.\r\n\r\n\"C\u00e1ch\r\n

        Nh\u1eadp c\u00f4ng th\u1ee9c => ch\u1ecdn bi\u1ec3u t\u01b0\u1ee3ng ph\u1ea7n tr\u0103m nh\u01b0 \u1ea3nh<\/em><\/p>\r\n\r\n

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        • Ngo\u00e0i ra, n\u1ebfu mu\u1ed1n t\u00ednh ph\u1ea7n tr\u0103m m\u1ed9t \u00f4 tr\u00ean m\u1ed9t t\u1ed5ng, c\u00e1c b\u1ea1n c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng c\u00f4ng th\u1ee9c tham chi\u1ebfu nh\u01b0 v\u00ed d\u1ee5 d\u01b0\u1edbi \u0111\u00e2y:<\/li>\r\n<\/ul>\r\nV\u00ed d\u1ee5: N\u1ebfu mu\u1ed1n t\u00ednh ph\u1ea7n tr\u0103m c\u1ee7a \u00f4 C2 v\u1edbi t\u1ed5ng \u00f4 C7 v\u00e0 \u00f4 C7 c\u00e1c b\u1ea1n \u0111\u1ec3 h\u00e0m Sum th\u00ec h\u00e3y s\u1eed d\u1ee5ng tham chi\u1ebfu: $C$7 => c\u00f4ng th\u1ee9c: C2\/ $C$7<\/strong>\r\n\r\nVi\u1ec7c s\u1eed d\u1ee5ng tham chi\u1ebfu ph\u00f9 h\u1ee3p khi \u00f4 \u0111\u01b0\u1ee3c tham chi\u1ebfu c\u00f3 gi\u00e1 tr\u1ecb ph\u1ee5 thu\u1ed9c v\u00e0o c\u00e1c \u00f4 kh\u00e1c. Nh\u01b0 trong v\u00ed d\u1ee5 th\u00ec \u00f4 C7 \u0111\u1eb7t h\u00e0m Sum, gi\u00e1 tr\u1ecb ph\u1ee5 thu\u1ed9c v\u00e0o c\u00e1c \u00f4 t\u1eeb C2 \u0111\u1ebfn C6. Khi b\u1ea1n s\u1eed d\u1ee5ng c\u00f4ng th\u1ee9c c\u00f3 ch\u1ee9a tham s\u1ed1 th\u00ec d\u00f9 gi\u00e1 tr\u1ecb \u1edf c\u00e1c \u00f4 C2 \u0111\u1ebfn C6 thay \u0111\u1ed5i, c\u00e1c b\u1ea1n v\u1eabn \u0111\u01b0\u1ee3c tr\u1ea3 v\u1ec1 k\u1ebft qu\u1ea3 \u0111\u00fang t\u01b0\u01a1ng \u1ee9ng v\u1edbi s\u1ef1 thay \u0111\u1ed5i \u0111\u00f3.\r\n\r\n\"C\u00f4ng\r\n

          Nh\u1eadp c\u00f4ng th\u1ee9c c\u00f3 tham chi\u1ebfu nh\u01b0 h\u00ecnh<\/em><\/p>\r\nK\u1ebft lu\u1eadn:<\/strong> Tr\u00ean \u0111\u00e2y, Ben Computer \u0111\u00e3 \u0111\u01b0a ra cho c\u00e1c b\u1ea1n chi ti\u1ebft c\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m c\u01a1 b\u1ea3n c\u0169ng nh\u01b0 nh\u1eefng \u1ee9ng d\u1ee5ng c\u1ee7a n\u00f3 trong cu\u1ed9c s\u1ed1ng. Hy v\u1ecdng b\u00e0i vi\u1ebft \u0111\u00e3 \u0111\u00e1p \u1ee9ng \u0111\u1ea7y \u0111\u1ee7 th\u00f4ng tin c\u00e1c b\u1ea1n c\u1ea7n. N\u1ebfu c\u00f3 b\u1ea5t c\u1ee9 th\u1eafc m\u1eafc n\u00e0o c\u1ea7n gi\u1ea3i th\u00edch th\u00eam, h\u00e3y comment xu\u1ed1ng ph\u00eda d\u01b0\u1edbi \u0111\u1ec3 Ben Computer bi\u1ebft nh\u00e9!\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t

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          \"\u2728\" Laptop Dell Inspiron 15 3520 \u2013 Ch\u1ea5t l\u01b0\u1ee3ng v\u01b0\u1ee3t tr\u1ed9i, gi\u00e1 si\u00eau \u01b0u \u0111\u00e3i! Kh\u1edfi \u0111\u1ea7u h\u00e0nh tr\u00ecnh h\u1ecdc t\u1eadp, l\u00e0m vi\u1ec7c c\u00f9ng Intel Core i5 m\u1ea1nh m\u1ebd, RAM 8GB.<\/b><\/span><\/p>\n

          \"\u2728\" <\/span>Qu\u00e0 t\u1eb7ng th\u00eam<\/strong>
          – T\u00fai\/ Balo + Chu\u1ed9t quang kh\u00f4ng d\u00e2y cao c\u1ea5p
          Kh\u00e1ch h\u00e0ng \u0111\u01b0\u1ee3c t\u1eb7ng th\u00eam 1 trong 3 qu\u00e0 t\u1eb7ng khi mua s\u1ea3n ph\u1ea9m:<\/strong>
          – Gi\u1ea3m ngay 300.000\u0111 cho kh\u00e1ch h\u00e0ng l\u00e0 h\u1ecdc sinh\/ sinh vi\u00ean
          – USB Hiksemi HS-USB-E301 32GB 3.2 Grey
          – Tai nghe Kanen K60<\/p>\n

          \"\ud83d\udc49\" \u0110\u0103ng k\u00fd ngay \u0111\u1ec3 nh\u1eadn \u01b0u \u0111\u00e3i \u0111\u1eb7c bi\u1ec7t d\u00e0nh ri\u00eang cho b\u1ea1n.
          Ti\u1ebft ki\u1ec7m 1.389.000\u0111!<\/span><\/span><\/strong><\/span><\/p>\t\t\t\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t

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